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106x^2+6x-100=0
a = 106; b = 6; c = -100;
Δ = b2-4ac
Δ = 62-4·106·(-100)
Δ = 42436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{42436}=206$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-206}{2*106}=\frac{-212}{212} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+206}{2*106}=\frac{200}{212} =50/53 $
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